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Maharashtra HSC · Class XII · Physics

Chapter 10: Magnetic Fields due to Electric Current

Full revision notes for Chapter 10 - Magnetic Fields due to Electric Current.

10.1

Biot-Savart Law

dB⃗=μ04π I dl⃗×r⃗r3d\vec{B} = \frac{\mu_0}{4\pi}\,\frac{I\,d\vec{l}\times\vec{r}}{r^3}
dB=μ04π I dl sin⁡θr2dB = \frac{\mu_0}{4\pi}\,\frac{I\,dl\,\sin\theta}{r^2}

Field due to a current element. II current, dldl element length, rr distance, θ\theta angle between the element and the radius vector and μ0=4π×10−7\mu_0 = 4\pi\times 10^{-7} N/A² the permeability of free space.

Long straight wire (infinite)

B=μ0I2πrB = \frac{\mu_0 I}{2\pi r}

At perpendicular distance rr from a very long (effectively infinite) wire. Field lines are concentric circles; direction from the right-hand rule.

Circular loop (radius R)

Bcenter=μ0I2RBN,center=μ0NI2RB_{center} = \frac{\mu_0 I}{2R} \qquad B_{N,center} = \frac{\mu_0 N I}{2R}
Baxis(x)=μ0IR22 (R2+x2)3/2B_{axis}(x) = \frac{\mu_0 I R^2}{2\,(R^2 + x^2)^{3/2}}

Center field for a single loop and for NN turns; on the axis at distance xx from the center. For a circular arc subtending angle θ\theta, B=μ0Iθ/(4πR)B = \mu_0 I\theta/(4\pi R).

10.2

Ampère's Circuital Law and Solenoids

Ampère's law

∮B⃗⋅dl⃗=μ0Ienclosed\oint \vec{B}\cdot d\vec{l} = \mu_0 I_{enclosed}

The line integral of B⃗\vec{B} around a closed path equals μ0\mu_0 times the net current enclosed. Useful for highly symmetric geometries.

Long solenoid

B=μ0nIB = \mu_0 n I

n=N/Ln = N/L turns per unit length. Uniform, strong field inside; nearly zero outside (ideal, long solenoid).

Toroid

B=μ0NI2πrB = \frac{\mu_0 N I}{2\pi r}

Inside the toroid at radius rr, for NN turns; field is confined to the interior (ideal toroid).

10.3

Forces on Charges and Currents

Force on a moving charge

F⃗=q v⃗×B⃗F=qvBsin⁡θ\vec{F} = q\,\vec{v}\times\vec{B} \qquad F = qvB\sin\theta

Magnetic force on a charge; perpendicular to both velocity and field, so it does no work. Lorentz force with an electric field: F⃗=q(E⃗+v⃗×B⃗)\vec{F} = q(\vec{E} + \vec{v}\times\vec{B}). Field units: tesla (T).

Force on a current-carrying wire

F=BIlsin⁡θF = B I l \sin\theta

Force on a straight wire of length ll carrying current II at angle θ\theta to the field.

Force between two parallel wires

Fl=μ0I1I22πd\frac{F}{l} = \frac{\mu_0 I_1 I_2}{2\pi d}

Force per unit length between parallel wires separated by dd. Parallel currents attract, antiparallel currents repel. This defines the ampere.

10.4

Moving-Coil Galvanometer and Conversion

Galvanometer

θ∝Iθ=NBACI\theta \propto I \qquad \theta = \frac{N B A}{C}I

Deflection proportional to current. NN turns, BB field, AA coil area and CC the torsional constant. Current sensitivity θ/I=NBA/C\theta/I = NBA/C; voltage sensitivity θ/V=NBA/(C G)\theta/V = NBA/(C\,G) with galvanometer resistance GG.

To an ammeter (low shunt in parallel)

S=IgGI−IgS = \frac{I_g G}{I - I_g}

Shunt SS carries the excess current; IgI_g is the full-scale galvanometer current and II the new range. Ammeters are low-resistance, connected in series.

To a voltmeter (high multiplier in series)

R=VIg−GR = \frac{V}{I_g} - G

Series resistance RR extends the range to VV. Voltmeters are high-resistance, connected in parallel.