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Maharashtra HSC · Class XII · Physics

Chapter 3: Kinetic Theory of Gases & Radiation

Full revision notes for Chapter 3 - Kinetic Theory of Gases & Radiation.

3.1

Ideal Gas and Gas Laws

PV=nRT=NNART=NkBTPV = nRT = \frac{N}{N_A}RT = N k_B T

PP pressure (Pa), VV volume (m³), nn number of moles, TT absolute temperature (K), RR universal gas constant (8.314 J/mol·K), NN number of molecules, NAN_A Avogadro number and kBk_B the Boltzmann constant (R/NAR/N_A).

3.2

Kinetic Theoretic Pressure and Speeds

Pressure from kinetic theory

P=13ρvrms2=13 n m vrms2P = \frac13 \rho v_{rms}^2 = \frac13\, n\, m\, v_{rms}^2

ρ\rho gas density, nn molecule number density, mm mass of one molecule and vrms=v2‾v_{rms} = \sqrt{\overline{v^2}} the root-mean-square speed.

rms, average and most-probable speeds

vrms=3RTM=3kBTmv_{rms} = \sqrt{\frac{3RT}{M}} = \sqrt{\frac{3k_B T}{m}}
vavg=8RTπMvmp=2RTMv_{avg} = \sqrt{\frac{8RT}{\pi M}} \qquad v_{mp} = \sqrt{\frac{2RT}{M}}

MM is the molar mass (kg/mol). The ratio is vrms:vavg:vmp=3:8/π:2v_{rms} : v_{avg} : v_{mp} = \sqrt{3} : \sqrt{8/\pi} : \sqrt{2}.

Translational kinetic energy

12mvrms2=32kBTper molecule\tfrac12 m v_{rms}^2 = \tfrac32 k_B T \qquad \text{per molecule}
KE‾avg=32RTper mole\overline{KE}_{avg} = \tfrac32 R T \qquad \text{per mole}

The mean translational kinetic energy depends on temperature alone, connecting microscopic motion to temperature.

3.3

Blackbody Radiation

Blackbody and Féry's blackbody

A perfect blackbody absorbs all radiation incident on it and, in thermal equilibrium, radiates the maximum possible energy for its temperature. Féry's blackbody is a hollow box with a small hole: any ray entering the cavity is effectively trapped (multiple reflections), so the hole acts as a near-ideal blackbody.

Stefan-Boltzmann law

E=σSB T4E = \sigma_{SB}\, T^4

The power radiated per unit area of a blackbody at absolute temperature TT. σSB=5.67×10−8\sigma_{SB} = 5.67\times 10^{-8} W/m²K⁴. Net power emitted into surroundings at T0T_0: P=σSBA (T4−T04)P = \sigma_{SB} A\,(T^4 - T_0^4).

Wien's displacement law

λmax T=b\lambda_{max}\,T = b

λmax\lambda_{max} is the wavelength of peak emission, TT temperature and b=2.898×10−3b = 2.898\times 10^{-3} m·K. Hotter bodies radiate most energy at shorter wavelengths.

Kirchhoff's law of radiation

At thermal equilibrium, for matched wavelength and direction, the spectral emissive power eλe_\lambda equals the spectral absorptivity aλa_\lambda. A good absorber is a good emitter: bodies radiate and absorb in proportion to their absorptivity.