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Maharashtra HSC · Class XII · Physics

Chapter 8: Electrostatics

Full revision notes for Chapter 8 - Electrostatics.

8.1

Coulomb's Law and Electric Field

F=14πε0 q1q2r2F = \frac{1}{4\pi\varepsilon_0}\,\frac{q_1 q_2}{r^2}

Force between point charges. ε0=8.85×10−12\varepsilon_0 = 8.85\times 10^{-12} C²/(N·m²) is the permittivity of free space; like charges repel, unlike attract.

Electric field

E⃗=F⃗q0E=14πε0qr2\vec{E} = \frac{\vec{F}}{q_0} \qquad E = \frac{1}{4\pi\varepsilon_0}\frac{q}{r^2}

Field is force per unit positive test charge; units N/C = V/m. Fields superpose vectorially.

Potential gradient

E⃗=−dVdr  r^\vec{E} = -\frac{dV}{dr}\;\hat{r}
8.2

Gauss's Law and its Applications

Electric flux and Gauss's law

∮E⃗⋅dA⃗=qenclosedε0\oint \vec{E}\cdot d\vec{A} = \frac{q_{enclosed}}{\varepsilon_0}

The closed-surface flux of E⃗\vec{E} equals the net charge enclosed over ε0\varepsilon_0. Distinct from electric potential VV - the flux ΦE\Phi_E carries the dot symbol.

Applications (symmetric geometries)

Charged conducting shell/sphere: inside the conductor the field is zero (E=0E = 0, charge resides on the surface); outside it behaves like a point charge at the centre, E=kQ/r2E = kQ/r^2.

Uniformly charged solid sphere (radius R): inside, E=Qr4πε0R3E = \frac{Q r}{4\pi\varepsilon_0 R^3} (proportional to rr); outside, point-like E=kQ/r2E = kQ/r^2.

Infinite line/cylinder (charge/unit length λ\lambda): E=λ2πε0rE = \frac{\lambda}{2\pi\varepsilon_0 r} radial, for large length compared with distance.

Infinite plane sheet (surface charge σ\sigma): E=σ2ε0E = \frac{\sigma}{2\varepsilon_0} uniform on each side. Between two parallel plates (opposite charge), E=σ/ε0E = \sigma/\varepsilon_0.

8.3

Electric Potential

Point charge

V=14πε0qrV = \frac{1}{4\pi\varepsilon_0}\frac{q}{r}

Work done per unit charge in bringing a test charge from infinity. Units: volt (V) = J/C.

Electric dipole (far-field approximation)

V≈14πε0pcos⁡θr2(r≫d)V \approx \frac{1}{4\pi\varepsilon_0}\frac{p\cos\theta}{r^2} \qquad (r \gg d)

p=qdp = qd is the dipole moment, θ\theta the angle with the axis. Far-field fields: on the axis E=2kp/r3E = 2kp/r^3, on the equator E=kp/r3E = kp/r^3. Dipole in a uniform field has torque τ=pEsin⁡θ\tau = pE\sin\theta and potential energy U=−pEcos⁡θU = -pE\cos\theta.

8.4

Capacitance and Energy

Defining relation and parallel-plate capacitor

C=QVC=ε0AdC = \frac{Q}{V} \qquad C = \frac{\varepsilon_0 A}{d}

QQ charge, VV potential difference, AA plate area and dd separation. Units: farad (F).

With a dielectric

C=κC0=κε0AdC = \kappa C_0 = \frac{\kappa\varepsilon_0 A}{d}

A dielectric uniformly filling the capacitor multiplies capacitance by its relative permittivity κ\kappa. (Full filling is assumed; the result differs if insertion is only partial.) Combinations: series 1/Ceq=∑1/Ci1/C_{eq} = \sum 1/C_i, parallel Ceq=∑CiC_{eq} = \sum C_i.

Energy stored in a capacitor

U=12QV=12CV2=Q22CU = \frac12 QV = \frac12 C V^2 = \frac{Q^2}{2C}

Stored electrostatic energy, equivalently expressed. The energy density between the plates is u=12ε0E2u = \frac12 \varepsilon_0 E^2 (J/m³).